Kinetic Engergy

Description

This program calculates an interchangeable solution among the variables weight (or mass), velocity, and kinetic energy, for an object moving at constant velocity. The program operates in either English or metric units. For metric units, any consistent set of units may be used; the quantity mass must be used. For English units, the enery must be in a foot-pounds, the velocity in feet per second, and the quantity weight in pounds.

Equations:
English:
         W
K.E. = ———— v2
        2g

Metric:
K.E. = 1/2 mv2

where:
K.E. = Kinetic Energy
W = Weight (lb)
m = Mass (kg, g)
v = Velocity
g = Acceleration due to gravity = 32.17398 ft/sec2

Instructions:
Example:

The slide of a slider-crank mechanism is used to punch holes in a slab of metal. It is found that the work required to punch a hole is 775 ft-lb. If the slider weights 5 lb 4 oz., how fast must it be moving when it strikes the metal?

B
775 STO 1
5 ENTER 4 ENTER 16 ÷ + STO 2
GSB 3 → 97.4627 (ft/sec)

Program Resources

Labels

Name Description
 A Set SI or metric units
 B Set English units
 1 Calculate Kinetic Energy (K.E.)
 2 Calculate Weight (W) or mass (m)
 3 Calculate Velocity (v)

Storage Registers

Name Description
 0 Units adaptation factor
 1 Kinetic Energy K.E.
 2 Weight (W) or mass (m)
 3 Velocity (v)

Program

Line Display Key Sequence Line Display Key Sequence
000 022 10 ÷
001 42,21,11 f LBL A 023 44 1 STO 1
002 2 2 024 43 32 g RTN
003 44 0 STO 0 025 42,21, 2 f LBL 2
004 43 32 g RTN 026 45 1 RCL 1
005 42,21,12 f LBL B 027 45 3 RCL 3
006 6 6 028 43 11 g
007 4 4 029 10 ÷
008 48 . 030 45 0 RCL 0
009 3 3 031 20 ×
010 4 4 032 44 2 STO 2
011 7 7 033 43 32 g RTN
012 9 9 034 42,21, 3 f LBL 3
013 6 6 035 45 1 RCL 1
014 44 0 STO 0 036 45 2 RCL 2
015 43 32 g RTN 037 10 ÷
016 42,21, 1 f LBL 1 038 45 0 RCL 0
017 45 2 RCL 2 039 20 ×
018 45 3 RCL 3 040 11 √x̅
019 43 11 g 041 44 3 STO 3
020 20 × 042 43 32 g RTN
021 45 0 RCL 0