Circulo de Mohr 2D 1.1 - detailed information

Circulo de Mohr 2D

Description: In two dimensions, determines the maximum and minimum tension, from two measurements of the normal and tangential tension on two right angles.

Description (2): En dos dimensiones, permite determinar la tensión máxima y mínima, a partir de dos mediciones de la tensión normal y tangencial sobre dos ángulos que forman 90º.

Filename: mohr2d.zip

ID: 7738

Current version: 1.1

Author: Hebert Poma Vidal: https://www.facebook.com/HP-PRIME-programar-HWLabs-1702068820036255/

Downloaded file size: 8,856 bytes

Size on calculator: 10 KB

Platforms: Prime

User rating: 8/10 with 1 vote (you must be logged in to vote)

Primary category: Science

Languages: ESP

File date: 2017-02-10 21:28:33

Source code: Not included

Download count: 5,687

Version history: 2017-02-10: Added to site

Archive contents:

Length Date Time Name --------- ---------- ----- ---- 0 2017-02-08 23:47 circulo de mohr 2D .hpappdir/ 1344 2016-09-16 20:40 circulo de mohr 2D .hpappdir/circulo de mohr 2D .hpapp 2 2016-09-16 21:11 circulo de mohr 2D .hpappdir/circulo de mohr 2D .hpappnote 35964 2016-09-16 21:11 circulo de mohr 2D .hpappdir/circulo de mohr 2D .hpappprgm 2660 2016-09-16 20:31 circulo de mohr 2D .hpappdir/icon.png 1140 2016-09-16 21:14 leeme.txt --------- ------- 41110 6 files

Screenshot:

User comments: Brad Woollon
2017-04-28 11:58:34
I ran into issues using the following values:
σx=40
σy=-60
τxy=-30

My angle reading was -1774.09 Degrees for 2θ with these values whereas it should be 30.963 Degrees.

I solved this by replacing lines 64-68 which had:
ANG1:=90*3.14159265359/(180);
ELSE
ANG1:=atan(2*(C)/(A-B));
END;
ANG:=(ANG1)*180/3.14159265359;

To:
ANG1:=90*(3.14159265359/180);
ELSE
ANG:=atan(2*(C)/(B-A));
END;
ANG1:=(ANG)*(3.14159265359/180);

With that code, I now get the correct value with all the values I test it with.

I am not sure if something happened when I downloaded the code that made it incorrect, or if I managed to find a mistake.

I hope this helps, and thank you for the very useful program!

You must be logged in to add your own comment.